4[3+n]=[4*3]+[4*2]

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Solution for 4[3+n]=[4*3]+[4*2] equation: 


Simplifying
4[3 + n] = [4 * 3] + [4 * 2]
[3 * 4 + n * 4] = [4 * 3] + [4 * 2]
[12 + 4n] = [4 * 3] + [4 * 2]

Multiply 4 * 3
12 + 4n = [12] + [4 * 2]
12 + 4n = 12 + [4 * 2]

Multiply 4 * 2
12 + 4n = 12 + [8]
12 + 4n = 12 + 8

Combine like terms: 12 + 8 = 20
12 + 4n = 20

Solving
12 + 4n = 20

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 4n = 20 + -12

Combine like terms: 12 + -12 = 0
0 + 4n = 20 + -12
4n = 20 + -12

Combine like terms: 20 + -12 = 8
4n = 8

Divide each side by '4'.
n = 2

Simplifying
n = 2

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